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(7x-2)(3x-4)=0
We multiply parentheses ..
(+21x^2-28x-6x+8)=0
We get rid of parentheses
21x^2-28x-6x+8=0
We add all the numbers together, and all the variables
21x^2-34x+8=0
a = 21; b = -34; c = +8;
Δ = b2-4ac
Δ = -342-4·21·8
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{484}=22$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-34)-22}{2*21}=\frac{12}{42} =2/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-34)+22}{2*21}=\frac{56}{42} =1+1/3 $
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