(7x-16)(3x+19)=0

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Solution for (7x-16)(3x+19)=0 equation:



(7x-16)(3x+19)=0
We multiply parentheses ..
(+21x^2+133x-48x-304)=0
We get rid of parentheses
21x^2+133x-48x-304=0
We add all the numbers together, and all the variables
21x^2+85x-304=0
a = 21; b = 85; c = -304;
Δ = b2-4ac
Δ = 852-4·21·(-304)
Δ = 32761
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{32761}=181$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(85)-181}{2*21}=\frac{-266}{42} =-6+1/3 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(85)+181}{2*21}=\frac{96}{42} =2+2/7 $

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