(7x-15)=(3x-9)+(2x+20)

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Solution for (7x-15)=(3x-9)+(2x+20) equation: 



(7x-15)=(3x-9)+(2x+20)

We move all terms to the left:

(7x-15)-((3x-9)+(2x+20))=0

We get rid of parentheses

7x-((3x-9)+(2x+20))-15=0



We calculate terms in parentheses: -((3x-9)+(2x+20)), so:

(3x-9)+(2x+20)

We get rid of parentheses

3x+2x-9+20

We add all the numbers together, and all the variables

5x+11

Back to the equation:

-(5x+11)



We get rid of parentheses

7x-5x-11-15=0

We add all the numbers together, and all the variables

2x-26=0

We move all terms containing x to the left, all other terms to the right

2x=26

x=26/2

x=13

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