(7x-15)+(4x-3)+(x+28)=180

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Solution for (7x-15)+(4x-3)+(x+28)=180 equation: 



(7x-15)+(4x-3)+(x+28)=180

We move all terms to the left:

(7x-15)+(4x-3)+(x+28)-(180)=0

We get rid of parentheses

7x+4x+x-15-3+28-180=0

We add all the numbers together, and all the variables

12x-170=0

We move all terms containing x to the left, all other terms to the right

12x=170

x=170/12

x=14+1/6

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