(7x-11)(9x+19)=0

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Solution for (7x-11)(9x+19)=0 equation:



(7x-11)(9x+19)=0
We multiply parentheses ..
(+63x^2+133x-99x-209)=0
We get rid of parentheses
63x^2+133x-99x-209=0
We add all the numbers together, and all the variables
63x^2+34x-209=0
a = 63; b = 34; c = -209;
Δ = b2-4ac
Δ = 342-4·63·(-209)
Δ = 53824
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{53824}=232$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(34)-232}{2*63}=\frac{-266}{126} =-2+1/9 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(34)+232}{2*63}=\frac{198}{126} =1+4/7 $

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