(7x-102)+(3x-38)=180

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Solution for (7x-102)+(3x-38)=180 equation: 



(7x-102)+(3x-38)=180

We move all terms to the left:

(7x-102)+(3x-38)-(180)=0

We get rid of parentheses

7x+3x-102-38-180=0

We add all the numbers together, and all the variables

10x-320=0

We move all terms containing x to the left, all other terms to the right

10x=320

x=320/10

x=32

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