(7x-10)=(2x-8)+(3x+20)

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Solution for (7x-10)=(2x-8)+(3x+20) equation: 



(7x-10)=(2x-8)+(3x+20)

We move all terms to the left:

(7x-10)-((2x-8)+(3x+20))=0

We get rid of parentheses

7x-((2x-8)+(3x+20))-10=0



We calculate terms in parentheses: -((2x-8)+(3x+20)), so:

(2x-8)+(3x+20)

We get rid of parentheses

2x+3x-8+20

We add all the numbers together, and all the variables

5x+12

Back to the equation:

-(5x+12)



We get rid of parentheses

7x-5x-12-10=0

We add all the numbers together, and all the variables

2x-22=0

We move all terms containing x to the left, all other terms to the right

2x=22

x=22/2

x=11

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