(7x-10)+(3x+42)=360

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Solution for (7x-10)+(3x+42)=360 equation: 



(7x-10)+(3x+42)=360

We move all terms to the left:

(7x-10)+(3x+42)-(360)=0

We get rid of parentheses

7x+3x-10+42-360=0

We add all the numbers together, and all the variables

10x-328=0

We move all terms containing x to the left, all other terms to the right

10x=328

x=328/10

x=32+4/5

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