(7x-1)/3=(3-2x)/4

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Solution for (7x-1)/3=(3-2x)/4 equation: 



(7x-1)/3=(3-2x)/4

We move all terms to the left:

(7x-1)/3-((3-2x)/4)=0

We add all the numbers together, and all the variables

(7x-1)/3-((-2x+3)/4)=0

We calculate fractions


7x/()+(-((-2x+3)*3)/()=0



We calculate terms in parentheses: +(-((-2x+3)*3)/(), so:

-((-2x+3)*3)/(

We multiply all the terms by the denominator


-((-2x+3)*3)



We calculate terms in parentheses: -((-2x+3)*3), so:

(-2x+3)*3

We multiply parentheses

-6x+9

Back to the equation:

-(-6x+9)



We get rid of parentheses

6x-9

Back to the equation:

+(6x-9)



We get rid of parentheses

7x/()+6x-9=0

We multiply all the terms by the denominator


7x+6x*()-9*()=0

We add all the numbers together, and all the variables

7x+6x*()=0

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