(7x-1)(8x+1)=0

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Solution for (7x-1)(8x+1)=0 equation:



(7x-1)(8x+1)=0
We multiply parentheses ..
(+56x^2+7x-8x-1)=0
We get rid of parentheses
56x^2+7x-8x-1=0
We add all the numbers together, and all the variables
56x^2-1x-1=0
a = 56; b = -1; c = -1;
Δ = b2-4ac
Δ = -12-4·56·(-1)
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-15}{2*56}=\frac{-14}{112} =-1/8 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+15}{2*56}=\frac{16}{112} =1/7 $

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