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(7x-1)(6x-1)=180
We move all terms to the left:
(7x-1)(6x-1)-(180)=0
We multiply parentheses ..
(+42x^2-7x-6x+1)-180=0
We get rid of parentheses
42x^2-7x-6x+1-180=0
We add all the numbers together, and all the variables
42x^2-13x-179=0
a = 42; b = -13; c = -179;
Δ = b2-4ac
Δ = -132-4·42·(-179)
Δ = 30241
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-\sqrt{30241}}{2*42}=\frac{13-\sqrt{30241}}{84} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+\sqrt{30241}}{2*42}=\frac{13+\sqrt{30241}}{84} $
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