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(7x-1)(4x+3)=360
We move all terms to the left:
(7x-1)(4x+3)-(360)=0
We multiply parentheses ..
(+28x^2+21x-4x-3)-360=0
We get rid of parentheses
28x^2+21x-4x-3-360=0
We add all the numbers together, and all the variables
28x^2+17x-363=0
a = 28; b = 17; c = -363;
Δ = b2-4ac
Δ = 172-4·28·(-363)
Δ = 40945
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-\sqrt{40945}}{2*28}=\frac{-17-\sqrt{40945}}{56} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+\sqrt{40945}}{2*28}=\frac{-17+\sqrt{40945}}{56} $
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