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(7x-1)(1+7x)-x(49x-3)=6
We move all terms to the left:
(7x-1)(1+7x)-x(49x-3)-(6)=0
We add all the numbers together, and all the variables
(7x-1)(7x+1)-x(49x-3)-6=0
We use the square of the difference formula
49x^2-x(49x-3)-1-6=0
We multiply parentheses
49x^2-49x^2+3x-1-6=0
We add all the numbers together, and all the variables
3x-7=0
We move all terms containing x to the left, all other terms to the right
3x=7
x=7/3
x=2+1/3
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