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(7x+9)+(5x+11)=(9x+1)
We move all terms to the left:
(7x+9)+(5x+11)-((9x+1))=0
We get rid of parentheses
7x+5x-((9x+1))+9+11=0
We calculate terms in parentheses: -((9x+1)), so:We add all the numbers together, and all the variables
(9x+1)
We get rid of parentheses
9x+1
Back to the equation:
-(9x+1)
12x-(9x+1)+20=0
We get rid of parentheses
12x-9x-1+20=0
We add all the numbers together, and all the variables
3x+19=0
We move all terms containing x to the left, all other terms to the right
3x=-19
x=-19/3
x=-6+1/3
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