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(7x+8)(9x-4)=180
We move all terms to the left:
(7x+8)(9x-4)-(180)=0
We multiply parentheses ..
(+63x^2-28x+72x-32)-180=0
We get rid of parentheses
63x^2-28x+72x-32-180=0
We add all the numbers together, and all the variables
63x^2+44x-212=0
a = 63; b = 44; c = -212;
Δ = b2-4ac
Δ = 442-4·63·(-212)
Δ = 55360
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{55360}=\sqrt{64*865}=\sqrt{64}*\sqrt{865}=8\sqrt{865}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(44)-8\sqrt{865}}{2*63}=\frac{-44-8\sqrt{865}}{126} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(44)+8\sqrt{865}}{2*63}=\frac{-44+8\sqrt{865}}{126} $
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