(7x+7)(5x+27)=90

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Solution for (7x+7)(5x+27)=90 equation:



(7x+7)(5x+27)=90
We move all terms to the left:
(7x+7)(5x+27)-(90)=0
We multiply parentheses ..
(+35x^2+189x+35x+189)-90=0
We get rid of parentheses
35x^2+189x+35x+189-90=0
We add all the numbers together, and all the variables
35x^2+224x+99=0
a = 35; b = 224; c = +99;
Δ = b2-4ac
Δ = 2242-4·35·99
Δ = 36316
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{36316}=\sqrt{4*9079}=\sqrt{4}*\sqrt{9079}=2\sqrt{9079}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(224)-2\sqrt{9079}}{2*35}=\frac{-224-2\sqrt{9079}}{70} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(224)+2\sqrt{9079}}{2*35}=\frac{-224+2\sqrt{9079}}{70} $

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