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(7x+6)(5x-4)-(3x+2)(x-1)=(8x+5)(4x-3)
We move all terms to the left:
(7x+6)(5x-4)-(3x+2)(x-1)-((8x+5)(4x-3))=0
We multiply parentheses ..
(+35x^2-28x+30x-24)-(3x+2)(x-1)-((8x+5)(4x-3))=0
We calculate terms in parentheses: -((8x+5)(4x-3)), so:We get rid of parentheses
(8x+5)(4x-3)
We multiply parentheses ..
(+32x^2-24x+20x-15)
We get rid of parentheses
32x^2-24x+20x-15
We add all the numbers together, and all the variables
32x^2-4x-15
Back to the equation:
-(32x^2-4x-15)
35x^2-32x^2-28x+30x-(3x+2)(x-1)+4x-24+15=0
We multiply parentheses ..
35x^2-32x^2-(+3x^2-3x+2x-2)-28x+30x+4x-24+15=0
We add all the numbers together, and all the variables
3x^2-(+3x^2-3x+2x-2)+6x-9=0
We get rid of parentheses
3x^2-3x^2+3x-2x+6x+2-9=0
We add all the numbers together, and all the variables
7x-7=0
We move all terms containing x to the left, all other terms to the right
7x=7
x=7/7
x=1
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