(7x+56)+(2x-10)=97

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Solution for (7x+56)+(2x-10)=97 equation: 



(7x+56)+(2x-10)=97

We move all terms to the left:

(7x+56)+(2x-10)-(97)=0

We get rid of parentheses

7x+2x+56-10-97=0

We add all the numbers together, and all the variables

9x-51=0

We move all terms containing x to the left, all other terms to the right

9x=51

x=51/9

x=5+2/3

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