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(7x+49)(x-9)=0
We multiply parentheses ..
(+7x^2-63x+49x-441)=0
We get rid of parentheses
7x^2-63x+49x-441=0
We add all the numbers together, and all the variables
7x^2-14x-441=0
a = 7; b = -14; c = -441;
Δ = b2-4ac
Δ = -142-4·7·(-441)
Δ = 12544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{12544}=112$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-112}{2*7}=\frac{-98}{14} =-7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+112}{2*7}=\frac{126}{14} =9 $
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