(7x+4)+(5x+4)+(4x+9)+(4x+1)(9x-6)=360

Solution for (7x+4)+(5x+4)+(4x+9)+(4x+1)(9x-6)=360 equation:

(7x+4)+(5x+4)+(4x+9)+(4x+1)(9x-6)=360

We move all terms to the left:

(7x+4)+(5x+4)+(4x+9)+(4x+1)(9x-6)-(360)=0

We get rid of parentheses

7x+5x+4x+(4x+1)(9x-6)+4+4+9-360=0

We multiply parentheses ..

(+36x^2-24x+9x-6)+7x+5x+4x+4+4+9-360=0

We add all the numbers together, and all the variables

(+36x^2-24x+9x-6)+16x-343=0

We get rid of parentheses

36x^2-24x+9x+16x-6-343=0

We add all the numbers together, and all the variables

36x^2+x-349=0

a = 36; b = 1; c = -349;
Δ = b2-4ac
Δ = 12-4·36·(-349)
Δ = 50257
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{50257}}{2*36}=\frac{-1-\sqrt{50257}}{72}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{50257}}{2*36}=\frac{-1+\sqrt{50257}}{72}
$