(7x+3)=(4x+6)+(2x+16)

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Solution for (7x+3)=(4x+6)+(2x+16) equation: 



(7x+3)=(4x+6)+(2x+16)

We move all terms to the left:

(7x+3)-((4x+6)+(2x+16))=0

We get rid of parentheses

7x-((4x+6)+(2x+16))+3=0



We calculate terms in parentheses: -((4x+6)+(2x+16)), so:

(4x+6)+(2x+16)

We get rid of parentheses

4x+2x+6+16

We add all the numbers together, and all the variables

6x+22

Back to the equation:

-(6x+22)



We get rid of parentheses

7x-6x-22+3=0

We add all the numbers together, and all the variables

x-19=0

We move all terms containing x to the left, all other terms to the right

x=19

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