(7x+3)+(16x-5)=90

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Solution for (7x+3)+(16x-5)=90 equation: 



(7x+3)+(16x-5)=90

We move all terms to the left:

(7x+3)+(16x-5)-(90)=0

We get rid of parentheses

7x+16x+3-5-90=0

We add all the numbers together, and all the variables

23x-92=0

We move all terms containing x to the left, all other terms to the right

23x=92

x=92/23

x=4

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