(7x+20)=(3x+100)

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Solution for (7x+20)=(3x+100) equation: 



(7x+20)=(3x+100)

We move all terms to the left:

(7x+20)-((3x+100))=0

We get rid of parentheses

7x-((3x+100))+20=0



We calculate terms in parentheses: -((3x+100)), so:

(3x+100)

We get rid of parentheses

3x+100

Back to the equation:

-(3x+100)



We get rid of parentheses

7x-3x-100+20=0

We add all the numbers together, and all the variables

4x-80=0

We move all terms containing x to the left, all other terms to the right

4x=80

x=80/4

x=20

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