(7x+2+21x-4)=70

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Solution for (7x+2+21x-4)=70 equation: 



(7x+2+21x-4)=70

We move all terms to the left:

(7x+2+21x-4)-(70)=0

We add all the numbers together, and all the variables

(28x-2)-70=0

We get rid of parentheses

28x-2-70=0

We add all the numbers together, and all the variables

28x-72=0

We move all terms containing x to the left, all other terms to the right

28x=72

x=72/28

x=2+4/7

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