(7x+2)+3x+32+58+90=180

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Solution for (7x+2)+3x+32+58+90=180 equation: 



(7x+2)+3x+32+58+90=180

We move all terms to the left:

(7x+2)+3x+32+58+90-(180)=0

We add all the numbers together, and all the variables

3x+(7x+2)=0

We get rid of parentheses

3x+7x+2=0

We add all the numbers together, and all the variables

10x+2=0

We move all terms containing x to the left, all other terms to the right

10x=-2

x=-2/10

x=-1/5

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