(7x+12)=(4x+33)

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Solution for (7x+12)=(4x+33) equation: 



(7x+12)=(4x+33)

We move all terms to the left:

(7x+12)-((4x+33))=0

We get rid of parentheses

7x-((4x+33))+12=0



We calculate terms in parentheses: -((4x+33)), so:

(4x+33)

We get rid of parentheses

4x+33

Back to the equation:

-(4x+33)



We get rid of parentheses

7x-4x-33+12=0

We add all the numbers together, and all the variables

3x-21=0

We move all terms containing x to the left, all other terms to the right

3x=21

x=21/3

x=7

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