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(7x+12)/(4x+3)=2/5
We move all terms to the left:
(7x+12)/(4x+3)-(2/5)=0
Domain of the equation: (4x+3)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
4x!=-3
x!=-3/4
x!=-3/4
x∈R
(7x+12)/(4x+3)-(+2/5)=0
We get rid of parentheses
(7x+12)/(4x+3)-2/5=0
We calculate fractions
(35x+60)/(20x+15)+(-8x-6)/(20x+15)=0
We multiply all the terms by the denominator
(35x+60)+(-8x-6)=0
We get rid of parentheses
35x-8x+60-6=0
We add all the numbers together, and all the variables
27x+54=0
We move all terms containing x to the left, all other terms to the right
27x=-54
x=-54/27
x=-2
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