(7x+11)=(3x+9)+(3x+23)

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Solution for (7x+11)=(3x+9)+(3x+23) equation: 



(7x+11)=(3x+9)+(3x+23)

We move all terms to the left:

(7x+11)-((3x+9)+(3x+23))=0

We get rid of parentheses

7x-((3x+9)+(3x+23))+11=0



We calculate terms in parentheses: -((3x+9)+(3x+23)), so:

(3x+9)+(3x+23)

We get rid of parentheses

3x+3x+9+23

We add all the numbers together, and all the variables

6x+32

Back to the equation:

-(6x+32)



We get rid of parentheses

7x-6x-32+11=0

We add all the numbers together, and all the variables

x-21=0

We move all terms containing x to the left, all other terms to the right

x=21

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