(7x+11)+48=(-7+4x)

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Solution for (7x+11)+48=(-7+4x) equation: 



(7x+11)+48=(-7+4x)

We move all terms to the left:

(7x+11)+48-((-7+4x))=0

We add all the numbers together, and all the variables

(7x+11)-((4x-7))+48=0

We get rid of parentheses

7x-((4x-7))+11+48=0



We calculate terms in parentheses: -((4x-7)), so:

(4x-7)

We get rid of parentheses

4x-7

Back to the equation:

-(4x-7)



We add all the numbers together, and all the variables

7x-(4x-7)+59=0

We get rid of parentheses

7x-4x+7+59=0

We add all the numbers together, and all the variables

3x+66=0

We move all terms containing x to the left, all other terms to the right

3x=-66

x=-66/3

x=-22

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