(7x+10)=(3x)+(2x+40)

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Solution for (7x+10)=(3x)+(2x+40) equation: 



(7x+10)=(3x)+(2x+40)

We move all terms to the left:

(7x+10)-((3x)+(2x+40))=0

We get rid of parentheses

7x-(3x+(2x+40))+10=0



We calculate terms in parentheses: -(3x+(2x+40)), so:

3x+(2x+40)

We get rid of parentheses

3x+2x+40

We add all the numbers together, and all the variables

5x+40

Back to the equation:

-(5x+40)



We get rid of parentheses

7x-5x-40+10=0

We add all the numbers together, and all the variables

2x-30=0

We move all terms containing x to the left, all other terms to the right

2x=30

x=30/2

x=15

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