(7x+10)/4=(3x-3)/2

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Solution for (7x+10)/4=(3x-3)/2 equation: 



(7x+10)/4=(3x-3)/2

We move all terms to the left:

(7x+10)/4-((3x-3)/2)=0

We calculate fractions


7x/()+(-((3x-3)*4)/()=0



We calculate terms in parentheses: +(-((3x-3)*4)/(), so:

-((3x-3)*4)/(

We multiply all the terms by the denominator


-((3x-3)*4)



We calculate terms in parentheses: -((3x-3)*4), so:

(3x-3)*4

We multiply parentheses

12x-12

Back to the equation:

-(12x-12)



We get rid of parentheses

-12x+12

Back to the equation:

+(-12x+12)



We get rid of parentheses

7x/()-12x+12=0

We multiply all the terms by the denominator


7x-12x*()+12*()=0

We add all the numbers together, and all the variables

7x-12x*()=0

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