(7x+10)(11x=-14)

Solution for (7x+10)(11x=-14) equation:

(7x+10)(11x=-14)

We move all terms to the left:

(7x+10)(11x-(-14))=0


We calculate terms in parentheses: +(7x+10)(11x-(-14)), so:

7x+10)(11x-(-14)

We add all the numbers together, and all the variables

7x+10)(11x+14

Back to the equation:

+(7x+10)(11x+14)


We multiply parentheses ..

(+77x^2+98x+110x+140)=0

We get rid of parentheses

77x^2+98x+110x+140=0

We add all the numbers together, and all the variables

77x^2+208x+140=0

a = 77; b = 208; c = +140;
Δ = b2-4ac
Δ = 2082-4·77·140
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(208)-12}{2*77}=\frac{-220}{154}
=-1+3/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(208)+12}{2*77}=\frac{-196}{154}
=-1+3/11
$