(7x+1)/(11)=(10x-12)/(6)

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Solution for (7x+1)/(11)=(10x-12)/(6) equation: 



(7x+1)/(11)=(10x-12)/(6)

We move all terms to the left:

(7x+1)/(11)-((10x-12)/(6))=0

We calculate fractions


7x/()+(-((10x-12)*11)/()=0



We calculate terms in parentheses: +(-((10x-12)*11)/(), so:

-((10x-12)*11)/(

We multiply all the terms by the denominator


-((10x-12)*11)



We calculate terms in parentheses: -((10x-12)*11), so:

(10x-12)*11

We multiply parentheses

110x-132

Back to the equation:

-(110x-132)



We get rid of parentheses

-110x+132

Back to the equation:

+(-110x+132)



We get rid of parentheses

7x/()-110x+132=0

We multiply all the terms by the denominator


7x-110x*()+132*()=0

We add all the numbers together, and all the variables

7x-110x*()=0

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