(7x+1)+(9x-2)=(10x+18)

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Solution for (7x+1)+(9x-2)=(10x+18) equation: 



(7x+1)+(9x-2)=(10x+18)

We move all terms to the left:

(7x+1)+(9x-2)-((10x+18))=0

We get rid of parentheses

7x+9x-((10x+18))+1-2=0



We calculate terms in parentheses: -((10x+18)), so:

(10x+18)

We get rid of parentheses

10x+18

Back to the equation:

-(10x+18)



We add all the numbers together, and all the variables

16x-(10x+18)-1=0

We get rid of parentheses

16x-10x-18-1=0

We add all the numbers together, and all the variables

6x-19=0

We move all terms containing x to the left, all other terms to the right

6x=19

x=19/6

x=3+1/6

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