(7x)/(x+4)-8=(2)/(x+4)

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Solution for (7x)/(x+4)-8=(2)/(x+4) equation: 


D( x )

x+4 = 0

x+4 = 0

x+4 = 0

x+4 = 0 // - 4

x = -4

x in (-oo:-4) U (-4:+oo)

(7*x)/(x+4)-8 = 2/(x+4) // - 2/(x+4)

(7*x)/(x+4)-(2/(x+4))-8 = 0

(7*x)/(x+4)-2*(x+4)^-1-8 = 0

(7*x)/(x+4)-2/(x+4)-8 = 0

(7*x)/(x+4)-2/(x+4)+(-8*(x+4))/(x+4) = 0

7*x-8*(x+4)-2 = 0

7*x-8*x-32-2 = 0

-x-34 = 0

(-x-34)/(x+4) = 0

(-x-34)/(x+4) = 0 // * x+4

-x-34 = 0

-x-34 = 0 // + 34

-x = 34 // * -1

x = -34

x = -34

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