(7x)+(3X-10)=65

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Solution for (7x)+(3X-10)=65 equation:


Simplifying
(7x) + (3X + -10) = 65

Reorder the terms:
(7x) + (-10 + 3X) = 65

Remove parenthesis around (-10 + 3X)
(7x) + -10 + 3X = 65

Reorder the terms:
-10 + 3X + (7x) = 65

Solving
-10 + 3X + (7x) = 65

Solving for variable 'X'.

Move all terms containing X to the left, all other terms to the right.

Add '10' to each side of the equation.
-10 + 3X + 10 + (7x) = 65 + 10

Reorder the terms:
-10 + 10 + 3X + (7x) = 65 + 10

Combine like terms: -10 + 10 = 0
0 + 3X + (7x) = 65 + 10
3X + (7x) = 65 + 10

Combine like terms: 65 + 10 = 75
3X + (7x) = 75

Add '(-7x)' to each side of the equation.
3X + (7x) + (-7x) = 75 + (-7x)

Combine like terms: (7x) + (-7x) = 0
3X + 0 = 75 + (-7x)
3X = 75 + (-7x)

Divide each side by '3'.
X = 25 + (-2.333333333x)

Simplifying
X = 25 + (-2.333333333x)

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