(7w+4)/2=25-(2w-6)/3

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Solution for (7w+4)/2=25-(2w-6)/3 equation: 



(7w+4)/2=25-(2w-6)/3

We move all terms to the left:

(7w+4)/2-(25-(2w-6)/3)=0

We calculate fractions


7w/()+(-(25-(2w-6)*2)/()=0



We calculate terms in parentheses: +(-(25-(2w-6)*2)/(), so:

-(25-(2w-6)*2)/(

We multiply all the terms by the denominator


-(25-(2w-6)*2)



We calculate terms in parentheses: -(25-(2w-6)*2), so:

25-(2w-6)*2

determiningTheFunctionDomain
-(2w-6)*2+25

We multiply parentheses

-4w+12+25

We add all the numbers together, and all the variables

-4w+37

Back to the equation:

-(-4w+37)



We get rid of parentheses

4w-37

Back to the equation:

+(4w-37)



We get rid of parentheses

7w/()+4w-37=0

We multiply all the terms by the denominator


7w+4w*()-37*()=0

We add all the numbers together, and all the variables

7w+4w*()=0

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