(7t-2)-(3t+)=-3(1-3t

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Solution for (7t-2)-(3t+)=-3(1-3t equation: 



(7t-2)-(3t+)=-3(1-3t

We move all terms to the left:

(7t-2)-(3t+)-(-3(1-3t)=0

We add all the numbers together, and all the variables

(7t-2)-(+3t)-(-3(-3t+1)=0

We get rid of parentheses

7t-3t-(-3(-3t+1)-2=0

We add all the numbers together, and all the variables

4t-(-3(-3t+1)-2=0

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