(7r+6)(8r+8)=90

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Solution for (7r+6)(8r+8)=90 equation:



(7r+6)(8r+8)=90
We move all terms to the left:
(7r+6)(8r+8)-(90)=0
We multiply parentheses ..
(+56r^2+56r+48r+48)-90=0
We get rid of parentheses
56r^2+56r+48r+48-90=0
We add all the numbers together, and all the variables
56r^2+104r-42=0
a = 56; b = 104; c = -42;
Δ = b2-4ac
Δ = 1042-4·56·(-42)
Δ = 20224
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{20224}=\sqrt{256*79}=\sqrt{256}*\sqrt{79}=16\sqrt{79}$
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(104)-16\sqrt{79}}{2*56}=\frac{-104-16\sqrt{79}}{112} $
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(104)+16\sqrt{79}}{2*56}=\frac{-104+16\sqrt{79}}{112} $

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