(7q-5)(7q+5)=0

Solution for (7q-5)(7q+5)=0 equation:

Simplifying
(7q + -5)(7q + 5) = 0

Reorder the terms:
(-5 + 7q)(7q + 5) = 0

Reorder the terms:
(-5 + 7q)(5 + 7q) = 0

Multiply (-5 + 7q) * (5 + 7q)
(-5(5 + 7q) + 7q * (5 + 7q)) = 0
((5 * -5 + 7q * -5) + 7q * (5 + 7q)) = 0
((-25 + -35q) + 7q * (5 + 7q)) = 0
(-25 + -35q + (5 * 7q + 7q * 7q)) = 0
(-25 + -35q + (35q + 49q2)) = 0

Combine like terms: -35q + 35q = 0
(-25 + 0 + 49q2) = 0
(-25 + 49q2) = 0

Solving
-25 + 49q2 = 0

Solving for variable 'q'.

Move all terms containing q to the left, all other terms to the right.

Add '25' to each side of the equation.
-25 + 25 + 49q2 = 0 + 25

Combine like terms: -25 + 25 = 0
0 + 49q2 = 0 + 25
49q2 = 0 + 25

Combine like terms: 0 + 25 = 25
49q2 = 25

Divide each side by '49'.
q2 = 0.5102040816

Simplifying
q2 = 0.5102040816

Take the square root of each side:
q = {-0.714285714, 0.714285714}