(7m-3)(7m+2)=0

Solution for (7m-3)(7m+2)=0 equation:

(7m-3)(7m+2)=0

We multiply parentheses ..

(+49m^2+14m-21m-6)=0

We get rid of parentheses

49m^2+14m-21m-6=0

We add all the numbers together, and all the variables

49m^2-7m-6=0

a = 49; b = -7; c = -6;
Δ = b2-4ac
Δ = -72-4·49·(-6)
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-35}{2*49}=\frac{-28}{98}
=-2/7
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+35}{2*49}=\frac{42}{98}
=3/7
$