(7k+6)(4k+1=)

Solution for (7k+6)(4k+1=) equation:

(7k+6)(4k+1=)

We move all terms to the left:

(7k+6)(4k+1-())=0


We calculate terms in parentheses: +(7k+6)(4k+1-()), so:

7k+6)(4k+1-()

We add all the numbers together, and all the variables

7k+6)(4k

Back to the equation:

+(7k+6)(4k)


We multiply parentheses

28k^2+24k=0

a = 28; b = 24; c = 0;
Δ = b2-4ac
Δ = 242-4·28·0
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-24}{2*28}=\frac{-48}{56}
=-6/7
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+24}{2*28}=\frac{0}{56}
=0
$