(7b-2)+(3b+2)=180

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Solution for (7b-2)+(3b+2)=180 equation: 



(7b-2)+(3b+2)=180

We move all terms to the left:

(7b-2)+(3b+2)-(180)=0

We get rid of parentheses

7b+3b-2+2-180=0

We add all the numbers together, and all the variables

10b-180=0

We move all terms containing b to the left, all other terms to the right

10b=180

b=180/10

b=18

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