(7a-4)=(3a+64)

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Solution for (7a-4)=(3a+64) equation: 



(7a-4)=(3a+64)

We move all terms to the left:

(7a-4)-((3a+64))=0

We get rid of parentheses

7a-((3a+64))-4=0



We calculate terms in parentheses: -((3a+64)), so:

(3a+64)

We get rid of parentheses

3a+64

Back to the equation:

-(3a+64)



We get rid of parentheses

7a-3a-64-4=0

We add all the numbers together, and all the variables

4a-68=0

We move all terms containing a to the left, all other terms to the right

4a=68

a=68/4

a=17

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