(7a-4)/5a=3

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Solution for (7a-4)/5a=3 equation: 



(7a-4)/5a=3

We move all terms to the left:

(7a-4)/5a-(3)=0



Domain of the equation: 5a!=0

a!=0/5

a!=0

a∈R



We multiply all the terms by the denominator


(7a-4)-3*5a=0

Wy multiply elements

(7a-4)-15a=0

We get rid of parentheses

7a-15a-4=0

We add all the numbers together, and all the variables

-8a-4=0

We move all terms containing a to the left, all other terms to the right

-8a=4

a=4/-8

a=-1/2

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