(7/i)-(2/5-i)

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Solution for (7/i)-(2/5-i) equation: 


D( i )

i = 0

i = 0

i = 0

i in (-oo:0) U (0:+oo)

i+7/i-(2/5) = 0

i+7/i-2/5 = 0

1*i^1+7*i^-1-2/5*i^0 = 0

(1*i^2-2/5*i^1+7*i^0)/(i^1) = 0 // * i^2

i^1*(1*i^2-2/5*i^1+7*i^0) = 0

i^1

i^2+(-2/5)*i+7 = 0

i^2+(-2/5)*i+7 = 0

DELTA = (-2/5)^2-(1*4*7)

DELTA = -696/25

DELTA < 0

i in { } 

i belongs to the empty set

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