(7/8)*p-4=10

Solution for (7/8)*p-4=10 equation:

(7/8)*p-4=10

We move all terms to the left:

(7/8)*p-4-(10)=0


Domain of the equation: 8)*p!=0

p!=0/1

p!=0

p∈R


We add all the numbers together, and all the variables

(+7/8)*p-4-10=0

We add all the numbers together, and all the variables

(+7/8)*p-14=0

We multiply parentheses

7p^2-14=0

a = 7; b = 0; c = -14;
Δ = b2-4ac
Δ = 02-4·7·(-14)
Δ = 392
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{392}=\sqrt{196*2}=\sqrt{196}*\sqrt{2}=14\sqrt{2}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-14\sqrt{2}}{2*7}=\frac{0-14\sqrt{2}}{14}
=-\frac{14\sqrt{2}}{14}
=-\sqrt{2}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+14\sqrt{2}}{2*7}=\frac{0+14\sqrt{2}}{14}
=\frac{14\sqrt{2}}{14}
=\sqrt{2}
$