(7/7b+3)=(2/b-3)

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Solution for (7/7b+3)=(2/b-3) equation: 



(7/7b+3)=(2/b-3)

We move all terms to the left:

(7/7b+3)-((2/b-3))=0



Domain of the equation: 7b+3)!=0

b∈R





Domain of the equation: b-3))!=0

b∈R



We get rid of parentheses

7/7b-((2/b-3))+3=0

We calculate fractions


7b/7b^2+(-((2*7b)/7b^2+3=0

We add all the numbers together, and all the variables

7b/7b^2+(-((+2*7b)/7b^2+3=0

We calculate fractions

We do not support ebpression: b^4

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