(7/6)+x(4/3)=-(121/6)

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Solution for (7/6)+x(4/3)=-(121/6) equation: 



(7/6)+x(4/3)=-(121/6)

We move all terms to the left:

(7/6)+x(4/3)-(-(121/6))=0

We add all the numbers together, and all the variables

x(+4/3)+(+7/6)-(-(+121/6))=0

We multiply parentheses

4x^2+(+7/6)-(-(+121/6))=0

We get rid of parentheses

4x^2+7/6-(-(+121/6))=0

We calculate fractions


4x^2=0

a = 4; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·4·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{8}=0$

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