(7/6)(3j+24)=(5/6)j+84

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Solution for (7/6)(3j+24)=(5/6)j+84 equation: 



(7/6)(3j+24)=(5/6)j+84

We move all terms to the left:

(7/6)(3j+24)-((5/6)j+84)=0



Domain of the equation: 6)(3j+24)!=0

j∈R





Domain of the equation: 6)j+84)!=0

j!=0/1

j!=0

j∈R



We add all the numbers together, and all the variables

(+7/6)(3j+24)-((+5/6)j+84)=0

We multiply parentheses ..

(+21j^2+7/6*24)-((+5/6)j+84)=0

We calculate fractions

We do not support ejpression: j^3

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